[(x^2-13)+(4-x)](0)=

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Solution for [(x^2-13)+(4-x)](0)= equation: 


Simplifying
[(x2 + -13) + (4 + -1x)](0) = 0

Reorder the terms:
[(-13 + x2) + (4 + -1x)](0) = 0

Remove parenthesis around (-13 + x2)
[-13 + x2 + (4 + -1x)](0) = 0

Remove parenthesis around (4 + -1x)
[-13 + x2 + 4 + -1x](0) = 0

Reorder the terms:
[-13 + 4 + -1x + x2](0) = 0

Combine like terms: -13 + 4 = -9
[-9 + -1x + x2](0) = 0

Reorder the terms for easier multiplication:
0[-9 + -1x + x2] = 0

Anything times zero is zero.
0[-9 + -1x + x2] = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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